初一数学计算题
2025-10-08
因为|ab-2|+（1-b）2=0 所以ab-2=0,1-b=0 所以ab=2,b=1,即a=2 所以原式=1/(1*2)+1/(2*3)+1/(3*4)+……+1/(2008*2009) =1-1/2+1/2-1/3+1/3-1/4+……+1/2008-1/2009 =1-1/2009...
2025-10-08
因为|ab-2|+（1-b）2=0 所以ab-2=0,1-b=0 所以ab=2,b=1,即a=2 所以原式=1/(1*2)+1/(2*3)+1/(3*4)+……+1/(2008*2009) =1-1/2+1/2-1/3+1/3-1/4+……+1/2008-1/2009 =1-1/2009...