各种初一数学计算题...
2025-10-08
计算 1、5ab³×(-4分之3a³b²)×(-3分之2ab^4c)³ =[5*(-3/4)*(-2/3)³]*[ab³*a³b²*(ab^4c)³] =[5*(-3/4)*(-8/27)]*[ab³*a³b²*a³b^12c³] =10/9*a^7b^17c³ 2、x(x-1)(x+3)-x²(x+1)+3x-1 =x(x²+2x-3)-x³-x²+3x-1...
2025-10-08
计算 1、5ab³×(-4分之3a³b²)×(-3分之2ab^4c)³ =[5*(-3/4)*(-2/3)³]*[ab³*a³b²*(ab^4c)³] =[5*(-3/4)*(-8/27)]*[ab³*a³b²*a³b^12c³] =10/9*a^7b^17c³ 2、x(x-1)(x+3)-x²(x+1)+3x-1 =x(x²+2x-3)-x³-x²+3x-1...